1550: Three-Consecutive-Odds
Easy

table of contents

Basically, just iterate through the array arr, and keep track of a count:

Then, after we check the parity of the element, we can simply return true if count == 3. Else, after all the iterations, we can simply just return false (since we never have 3 consecutive odd numbers).

code

class Solution {
public:
    bool threeConsecutiveOdds(vector<int>& arr) {
        int count = 0;
        for (int& i : arr) {
            if (i % 2 == 1) {
                ++count;
            } else {
                count = 0;
            }
            if (count == 3) {
                return true;
            }
        }
        return false;
    }
};

complexity

time taken